The remainder when $x^{6} - 3 x^{5} + 2 x^{2} + 8$ is divided by $x - 3$ is

24

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26

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8

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18

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Solution

The correct option is B $26$
Given $f (x) = x^{6} - 3 x^{5} + 12 x^{2} + 8$
and the divisor is $(x - 3)$
$\Rightarrow a = 3$
Therefore, according to remainder theorem
$R = f (a)$
$= f (3)$
$= (3)^{6} - 3 (3)^{5} + 2 (3)^{2} + 8$
$= (3)^{6} - 3^{6} + 26$
$= 26$

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Similar questions

3 x^{5} - 8 x^{4} - 5 x^{3} + 26 x^{2} - 33 x + 26

x^{3} - 2 x^{2} - 4 x + 8

3 x^{3} + 2 x^{2} - x + 4

3 + 2 x

\frac{- 1}{8}

When $3 x^{3} + 2 x^{2} - x + 4$ is divided by $3 + 2 x$ the remainder is $\frac{- 1}{8}$ .

The remainder when $3 x^{3} + 2 x^{2} - x + 4$ is divided by $3 + 2 x$ is $\frac{- 1}{8}$ .

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