You visited us 1 times! Enjoying our articles? Unlock Full Access!

Equivalent Resistance in Series Circuit

The resistanc...

Question

The resistance between the terminal point $A$ and $B$ of the given infinitely circuit will be:

(\sqrt{3} - 1)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(1 - \sqrt{3})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(1 + \sqrt{3})

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(2 + \sqrt{3})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $(1 + \sqrt{3})$
Let the resistance between A and B be R
The infinity series can be replaced by R parallel to $1 Ω$
$1 Ω$ is parallel to R and this is in series with $2 Ω$
$R = 2 Ω + \frac{R}{R + 1}$
$R^{2} - 2 R - 2 = 0$
On solving we get $R = 1 + \sqrt{3}$

Suggest Corrections

Similar questions

E_{1} = 7 V, E_{2} = 7 V, R_{1} = R_{2} = 1 Ω, R_{3} = 3 Ω

R_{3}

E

r

1 Ω

A

B

\sqrt{3} = 1.73

E_{1} = 3 V, E_{2} = 2 V, E_{3} = 1 V

r_{1} = r_{2} = r_{3} = 1 o h m

A

B

r_{2}

A

B

R

E_{1}, E_{2}, E_{3}

R

Join BYJU'S Learning Program