wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The resistance of 0.01 N solution at 25 is 200 ohm. Cell constant of the conductivity cell is unity. Calculate the equivalent conductance of the solution.

A
200 ohm1cm2eq1.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
300 ohm1cm2eq1.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
400 ohm1cm2eq1.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
500 ohm1cm2eq1.
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is B 500 ohm1cm2eq1.
since, we have
conductancecellconstant = specific conductance
cell consyant = 1
conductance = specific conductance= 1200

equivalent conductance= K1000N Scm2eq1

equivalent conductance= 110002000.01

equivalent conductance= 500 Scm2eq1

flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Conductance of Electrolytic Solution
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon