Question

The resistance of 0.01 N solution of an electrolyte AB at 328 K is 100 ohm. The specific conductance of solution is :

[ cell constant $=1c{m}^{-1}$ ]

• A. $100ohm$
• B. ${10}^{-2}oh{m}^{-1}$
• C. ${10}^{-2}oh{m}^{-1}c{m}^{-1}$
• D. ${10}^{2}ohm-cm$

Answer 1

Answer: (C)

${10}^{-2}oh{m}^{-1}c{m}^{-1}$

The specific conductance $\left(\kappa \right)$ is the product of reciprocal of resistance $\left(\frac{1}{R}\right)$ and cell constant $\left(\frac{l}{a}\right)$.

Hence, $\kappa =\frac{1}{R}\times \frac{l}{a}=\frac{1}{100ohm}\times 1{cm}^{-1}={10}^{-2}{ohm}^{-1}{cm}^{-1}$.

Hence, option C is correct.