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Question

The resistance of 0.01 N solution of an electrolyte is 210 Ω at 298 K with a cell constant of 0.88 cm1. Calculate the conductivity and equivalent conductivity of the solution.

A
4.19×103ohm1 cm1, 419.05 S cm2 eq1
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B
5.19×103ohm1 cm1, 519.05 S cm2 eq1
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C
6.19×103ohm1 cm1, 619.05 S cm2 eq1
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D
7.19×103ohm1 cm1, 719.05 S cm2 eq1
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Solution

The correct option is A 4.19×103ohm1 cm1, 419.05 S cm2 eq1
First check what is given in the question.
R=210 ohm and 1a=0.88cm1Now.K=1R×1a=1210×0.88=4.19×103ohm1cm1or S cm1eq=k×1000N=4.19×103×10000.01=419.05 S cm2 eq1

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