Question

The resistance of 0.01 N solution of an electrolyte is 210 $\Omega$ at 298 K with a cell constant of $0.88{cm}^{-1}$. Calculate the conductivity and equivalent conductivity of the solution.

Answer 1

$R=210\Omega$ $N=0.01N$ $x=\frac{l}{A}=0.88c{m}^{-1}$

$k=c.x=(\frac{1}{210}\times 0.88)$${\Omega }^{-1}c{m}^{-1}$$=conductivity=4.19\times {10}^{-3}$

${\Lambda }_{eq}$$=(k\times \frac{1000}{N})$$=(\frac{1}{210}\times \frac{0.88\times 1000}{0.01})$$=419.04Sc{m}^{2}e{q}^{-1}$