Question

The resistance of $0.1N$ solution of formic acid is $200ohm$ and cell constant is $2.0c{m}^{-1}.$ The equivalent conductivity (in $Sc{m}^{2}e{q}^{-1}$) of $0.1N$ formic acid is:

• A. 100
• B. 200
• C. 50
• D. 150

Answer 1

Answer: (A)

100

Equivalent conductivity $=\frac{k\times 1000}{\text{Normality}}$
$k=?$
$R=s\frac{L}{A}$
$C=k\frac{A}{l}$
$k=c\frac{l}{A}=\frac{1}{200ohm}\times 2c{m}^{-1}$

$=0.01oh{m}^{-1}c{m}^{-1}$

Equivalent $=\frac{1}{100}\times 1000\times 10$

$=100oh{m}^{-1}c{m}^{-1}$