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Question

The resistance of 0.5 M solution of an electrolyte in a conductivity cell was found to be 50 Ω. If the electrodes in the conductivity cell are 2.2 cm apart and have an area of 4.4 cm2 then the molar conductivity (in Sm2mol1) of the solution is

A
0.2
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B
0.02
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C
0.002
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D
None of these
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Solution

The correct option is C 0.002
conductivity,K=G1R
where G is the cell constant G=lA
where l is the distance between the electrodes and A is the area.

Therefore, K=150×2.24.4

= 0.01 Ω1cm1
molar conductivity, λm=K×1000C

=0.01×10000.5

= 20 Ω1cm2mol1

=0.002 Ω1m2mol1

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