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Question

The resistance of a 0.02 N solution of an electrolyte MgCl2 was found to be 210 ohm at 298 K using a conductivity cell with a cell constant of 0.88 cm1. Calculate the equivalent conductivity of the solution.

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Solution

Given:
Cell constant, lA=0.88 cm1Resistance, R=210 ohm

Specific conductance, κ=lA×1R

κ=0.88×1210=4.19×103ohm1cm1

Equivalent conductance is the conductivity of a solution containing 1 g-equivalent of the electrolyte.

Λeq=κ V
V is volume of solution containing 1 gequiv

Normality of solutionN
N gequiv of solute present in 1 L solution

1 gequiv of solute present in 1N L solution

Λeq=κN (when volume in litres)

Λeq=κ×1000N (when volume in cm3)

Λeq=4.19×103×10000.02


Λeq=209.5ohm1cm2eq1

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