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Question

The resistance of a 0.2 M solution of an electrolyte is 50 Ω. The specific conductance of the solution is 1.4 S m1 .
The resistance of a 0.5 M solution of the same electrolyte occupying the same volume is 280 Ω. The molar conductivity of the above mentioned 0.5 M solution of the electrolyte in S m2mol1 is:

A
5×103
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B
5×102
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C
5×103
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D
5×104
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Solution

The correct option is D 5×104

From the expression:
κ= G×C
We can say that, C= κG
As, G= 1R

C= κ×R
Since, ‘C’ remains constant for a cell.
We can say that,
κ1×R1 = κ2×R2
Putting values:
1.4×50 = κ2×280

k2= 14Sm1
Now,
ΛM= κ×1000M
1×1000×1094×0.5×103
Since, Molarity is defined per litre so we converted m3 to litre.
5×104Sm2mol1


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