Question

The resistance of a conductivity cell containing 0.001 M KCl solution at 298 K is $1500\Omega$. What is the cell constant if conductivity of 0.001 M KCl solution at 298 K is $1.46\times {10}^{-3}Sc{m}^{-1}$

Answer 1

\(R = 1500 \Omega ;

(conductivity of cell) k = 0.146 \times 10^{-3} S~cm^{-1}\)

Cell constant $=R\times k$

$=\left(1500\Omega \right)\times (0.146\times {10}^{-3}Sc{m}^{-1})=0.219c{m}^{-1}$

Cell constant $=0.219c{m}^{-1}$