Question

The resistance of a conductor is reduced to half its initial value keeping voltage applied constant. In doing so the heating effects in the conductor will become

• A. half
• B. double
• C. one-fourth
• D. four times

Answer 1

The correct option is B double

Heat energy generated in a resistor is given by , $E=\frac{V{}^2}{R}$

voltage is given constant. Hence $E\propto \frac{1}{R}$

So if we reduce the resistance to half of its value then heat generated will be doubled.