The resistance of each arm of the wheat stone bridge is 10Ω. A resistance of 10Ω is connected in series with galvanometer then the equivalent resistance across the battery will be :-
A
10Ω
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B
15Ω
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C
20Ω
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D
40Ω
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Solution
The correct option is A10Ω Here, P=Q=S=R=10Ω since PQ=SR=1, so it is balanced Wheatstone bridge and no current pass through galvanometer. As all arm resistances are equal so its equivalent resistance is also 10Ω.