Question

The resonant frequency of a circuit is f. If the capacitance is made 16 times the initial values, then the resonant frequency will become

• A. $\frac{f}{2}$
• B. $2f$
• C. $f$
• D. $\frac{f}{4}$

Answer 1

The correct option is D $\frac{f}{4}$

$f=\frac{1}{2\pi \sqrt{LC}}f\propto \frac{1}{\sqrt{c}}\Rightarrow f_2=\frac{f_1\sqrt{c_1}}{\sqrt{c_2}}\Rightarrow f_2=\frac{f}{4}$