The result of, 'y raised to the power 2, added to x raised to the power 3', multiplied by 5, gives

(y^{2} + x^{3}) \div 5

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(y^{2} + x^{3}) \times 5

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(y^{3} + x^{2}) \times 5

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Solution

The correct option is B $(y^{2} + x^{3}) \times 5$
y raised to the power 2 is $y^{2}$
x raised to the power 3 is $x^{3}$

So, y raised to the power 2 added to x raised to the power 3 is
$(y^{2} + x^{3})$

Now, multiplying this by 5, we get:
$(y^{2} + x^{3}) \times 5$

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The result of, 'y raised to the power 2, added to x raised to the power 3', multiplied by 5, gives

The correct option is B (y2+x3)×5y raised to the power 2 is y2 x raised to the power 3 is x3 So, y raised to the power 2 added to x raised to the power 3 is (y2+x3) Now, multiplying this by 5, we get: (y2+x3)×5

The correct option is B $(y^{2} + x^{3}) \times 5$
y raised to the power 2 is $y^{2}$
x raised to the power 3 is $x^{3}$

So, y raised to the power 2 added to x raised to the power 3 is
$(y^{2} + x^{3})$

Now, multiplying this by 5, we get:
$(y^{2} + x^{3}) \times 5$