The resultant capacitance (in μF) between the points A and B in the figure is
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Solution
If we redraw this circuit by looking at the potentials at points A,B,C,D,E and F then the circuit can be represented somewhat like this Now, we can clearly say, which all circuits are parallel and which all are in series.
For simplication let us rearrange it a bit further Thus, the total effective capacitance in between points A and B is 1Ceq=130μF+130μF ⟹Ceq=15μF