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Question

The resultant dipole moment of water is 1.85 D, Calculate the bond moment of OH bond (in D), bond angle in water molecule is 104o C. Given: cos 104o = -0.25 (Ignore the dipole moment due to lone pair)

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Solution

We know, dipole moment is a vector quantity
Let the dipole moment of OH bond be x D.
Using formula
R = P2+Q2+2PQcosθ
where R is the resultant dipole moment
P = Q is the dipole moment of each OH bond
put up values,
R = x2+x2+2x2cos104o
1.85=2x22x2×0.25
1.85=1.5x2
3.4225=1.5x2
On solving, x = 1.51 D

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