The resultant of two opposite parallel forces $12 N$ and $7 N$ is _____ N

12

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5

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19

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7

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Solution

The correct option is B $5$
${\to F}_{r e s u l t a n t} =_{1} +_{2}$
$∣ ∣_{1} +_{2} ∣ ∣ = \sqrt{F_{1}^{2} + F_{2}^{2} + 2 F_{1} F_{2} c o s θ}$
$θ = π$
$∣ ∣_{1} +_{2} ∣ ∣ = \sqrt{144 + 49 - 168}$
$= 5 N$

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The resultant of two opposite parallel forces 12 N and 7 N is _____ N

The correct option is B 5→Fresultant=→F1+→F2∣∣→F1+→F2∣∣=√F21+F22+2F1F2cosθ θ=π∣∣→F1+→F2∣∣=√144+49−168 =5N

The resultant of two opposite parallel forces $12 N$ and $7 N$ is _____ N

The correct option is B $5$
${\to F}_{r e s u l t a n t} =_{1} +_{2}$
$∣ ∣_{1} +_{2} ∣ ∣ = \sqrt{F_{1}^{2} + F_{2}^{2} + 2 F_{1} F_{2} c o s θ}$
$θ = π$
$∣ ∣_{1} +_{2} ∣ ∣ = \sqrt{144 + 49 - 168}$
$= 5 N$