Question

The reverse bias voltage in a P-N junction diode, is changed from $5\text{V}\text{to}15\text{V}$, then the value of current changes from $38\mu \text{A}\text{to}88\mu \text{A}$. The resistance of the junction diode will be

• A. $4\times {10}^5\Omega$
• B. $3\times {10}^5\Omega$
• C. $2\times {10}^5\Omega$
• D. ${10}^6\Omega$

Answer 1

The correct option is C $2\times {10}^5\Omega$

For a reverse bias
Change in voltage, $\Delta V=10\text{V}$
Change in current, $\Delta I=50\mu A$

Resistance for reverse bias is,

$R_r=\frac{\Delta V}{\Delta I}=\frac{10}{50\times {10}^{-6}}$

$\therefore R=2\times {10}^5\Omega$.

Hence, $\left(C\right)$ is the correct answer.