The reversible expansion of an ideal gas under adiabatic and isothermal conditions is shown in the fitgure. Which of the following statement(s) is (are) correct?

T_{1} = T_{2}

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T_{3} > T_{1}

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W_{i s o t h e r m a l} > W_{a d i a b a t i c}

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△ U_{i s o t h e r m a l} > △ U_{a d i a b a t i c}

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Solution

The correct option is D $△ U_{i s o t h e r m a l} > △ U_{a d i a b a t i c}$

(a) $T_{1} = T_{2}$ (due to isothermal) (correct)
(b) $T_{3} > T_{1}$ (Incorrect) cooling will take place in adiabatic expansion
(c) $W_{i s o t h e r m a l} > W_{a d i a b a t i c}$ (with sign, this is incorrect) with mode it should be correct.
(d) $△ U_{i s o t h e r m a l} = 0 > △ U_{a d i a b a t i c} = - v e$
$| W_{i s o b a r i c} | > | W_{i s o t h e r m a l} | > | W_{a d i a b a t i c} |$
So, answer is (a) and (b).

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