The Richardson equation is given by $I = {A T}^{2} e^{\frac{- B}{k T}}$ . The dimensional formula for ${A B}^{2}$ is same as that for:

{I T}^{- 2}

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k

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{I k}^{2}

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\frac{{I k}^{2}}{T}

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Solution

The correct option is A ${I k}^{2}$
$I = A T^{2} e^{\frac{- B}{k T}}$
Therefore dimension of A is $\frac{I}{T^{2}}$ , as the exponential term gives a real number.
Also B has dimension of $k T$ .
Therefore, dimension of $A B^{2} = I k^{2}$ .

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