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Question

The rise of the water level in a capillary tube of radius 0.07 cm when dipped vertically in a beaker containing water (assuming it to be perfectly wetting) will be.
Given : Surface tension of water is 0.07 Nm1 and g=10 ms2

A
2 cm
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B
4 cm
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C
1.5 cm
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D
3 cm
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Solution

The correct option is A 2 cm
Rise of a liquid in a capillary tube,
h=2Tcosθrρg
Here, r=0.07 cm=0.07×102 m
For water, T=0.07 Nm1,ρ=103 kg m3
Angle of contact θ=0, for perfectly wetting characteristics.
h=(2×0.07×1)(0.07×102)×(103)×(10)
h=2×102 m=2 cm

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