Question

# The rms speed (in m/s) of oxygen molecules of the gas at temperature $$300 K$$, is

A
483
B
504
C
377
D
346

Solution

## The correct option is A $$483$$The rms speed of a gas molecules at absolute temperature $$T$$ is given by:                  $$v_{rms}=\sqrt{\dfrac{3RT}{M}}$$where, $$R=8.31Jmol^{-1}K^{-1}$$  universal gas constant            $$M=$$ molar mass of gas in kgFor Oxygen, $$M=0.032kg/mol$$                      $$T=300K$$ (given)Therefore, $$v_{rms}$$ of Oxygen molecules will be:                  $$v_{rms}=\sqrt{\dfrac{3\times8.31\times300}{0.032}}=483\ m/s$$Physics

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