Question

The rms speed (in m/s) of oxygen molecules of the gas at temperature $300K$, is

• A. $483$
• B. $504$
• C. $377$
• D. $346$

Answer 1

The correct option is A $483$

The rms speed of a gas molecules at absolute temperature $T$ is given by:

$v_{rms}=\sqrt{\frac{3RT}{M}}$

where, $R=8.31Jmo{l}^{-1}{K}^{-1}$ universal gas constant

$M=$ molar mass of gas in kg

For Oxygen, $M=0.032kg/mol$

$T=300K$ (given)

Therefore, $v_{rms}$ of Oxygen molecules will be:

$v_{rms}=\sqrt{\frac{3\times 8.31\times 300}{0.032}}=483m/s$