Question

The roof of a house is of size $20m\times 15m$. It is to covered by rectangular tiles of $10cm\times 5cm$. How many tiles will be required? Also find the cost of tiling at the rate of $Rs525persq.$ metre.

Answer 1

Given Dimension of roof are $=20m\times 15m$

area of roof $20\times 15=300m^2$

area of 1 reactangular tile $=10\times 5=50c{m}^2$

then Total no. of tiles required $=\frac{areaofroof}{areaof1tile}$

Total no. of tiles $=\frac{300}{50}=60,000$

$\therefore$ 60,000 tiles are required

Now cost of tiles $300m^2=525\times 300Rs.$

Total cost $=15,7500Rs.$