The root mean square velocity of hydrogen is √5 times than that of nitrogen. If T is the temperature of the gas, then:
A
TH2=TN2
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B
TH2>TN2
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C
TH2<TN2
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D
TH2=√7TN2
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Solution
The correct option is CTH2<TN2 Vrns=√3RTM=(Vrns)H2(Vrns)N2=√TH2MH2×MN2TN2(Vrns)H2=√5(Vrns)N2∴(Vrns)H2(Vrns)H2×√5√TH2TN2×282⇒√51=√TH2TN2×14⇒5=TH2TN2×14⇒TN2×5=TH2×14∴TN2>TH2