The root mean square velocity of hydrogen molecules at $300$ K is $1930$ metre/sec Then the r.m.s.s velocti of oxygen molecules at $1200$ K will be:

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Solution

836m s
$V_{r m s} = \sqrt{\frac{3 R T}{M} =} \frac{V_{r m s} o 2}{V_{r m s} h 2} = \sqrt{\frac{T o 2}{T h 2}} \times \frac{M h 2}{M o 2}$
$\sqrt{\frac{900}{300} \times \frac{2}{32} =} \frac{\sqrt{3}}{4}$
836 ms

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