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Question

The roots of the equation 4x3.2x+2+32=0 are

A
1,2
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B
1,3
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C
2,3
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D
1,4
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Solution

The correct option is C 2,3
Given
4x32x+2+32=0
(2x)23(2x)(22)+32=0
(2x)212(2x)+32=0
Let2x=t
t212t+32=0
(t4)(t8)=0
t=4,8
2x=8
x=3
2x=4
x=2
Hencerootsare(2,3)

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