Question

The roots of the following quadratic equation are Real and equal.

$3x^2-4\sqrt{3}x+4=0$

• A. True
• B. False

Answer 1

The correct option is A True

$\Rightarrow$ The given quadratic equation is $3x^2-4\sqrt{3}x+4=0$, comparing it with $a{x}^2+bx+c=0$

$\Rightarrow$ We get, $a=3,b=-4\sqrt{3},c=4$

$\Rightarrow$ Discriminant $=b^2-4ac$

$=(-4\sqrt{3}{)}^2-4(3\left)\right(4)$

$=48-48$

$=0$

$\therefore$ Discriminant $=0$

$\therefore$ The roots of given equation are real and equal.