Question

The runway length after correcting for elevation and temperature is $2895m$. If the effective gradient on runway is $0.6$ percent, then the corrected runway length is ____ m

• A. 3242.4

Answer 1

The correct option is A 3242.4
Given, corrected length after applying elevation and temperature correction $=2895m$
Effective gradient $=0.6$%
$\therefore$ Correction for gradient $=\frac{20}{100}\times 2895\times 0.6=347.4m$
$\therefore$ Corrected runway length $=2895+347.4=3242.4m$