The same quantity of electricity is passed through Al2(SO4)3 and AgNO3 solution with platinum electrodes. If n number of Al atoms are deposited on the cathode, the number of Ag atoms deposited on the cathode will be:
A
n
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B
2n
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C
3n
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D
n/2
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Solution
The correct option is C 3n 1 F = 96500 C = 1 Eq of Al3+ = 1 Eq of Ag⨁ =13 mol of Al3+≡11 mol of Al⨁ = 1 mol of Al3+ = 3 mol of Ag⨁ = n atoms of Al3+ = 3n atoms of Ag⨁