The school book store sold 8 more pencils than pens one day. The cost of a pencil is $$ .05$ , and the cost of a pen is $$ .20$ . If the day's sales of pens and pencils totalled $$ 8.90$ , how many pencils were sold?

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Solution

The correct option is C 42
Amount of pens sold = p
Amount of pencils sold = p + 8
0.05(p + 8) + 0.20(p) = 8.90 each pen is $$ 0.20$ while each pencil is $$ 0.05$
0.05p + 0.4 + 0.20p = 8.90
0.25p = 8.50
Number of pens: 34
Number of pencils sold: 34 + 8 = 42
The correct option is C

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The school book store sold 8 more pencils than pens one day. The cost of a pencil is $.05, and the cost of a pen is $.20. If the day's sales of pens and pencils totalled $8.90, how many pencils were sold?

The correct option is C 42Amount of pens sold = p Amount of pencils sold = p + 8 0.05(p + 8) + 0.20(p) = 8.90 each pen is $0.20 while each pencil is $0.05 0.05p + 0.4 + 0.20p = 8.90 0.25p = 8.50 Number of pens: 34 Number of pencils sold: 34 + 8 = 42 The correct option is C

The school book store sold 8 more pencils than pens one day. The cost of a pencil is $$ .05$ , and the cost of a pen is $$ .20$ . If the day's sales of pens and pencils totalled $$ 8.90$ , how many pencils were sold?

The correct option is C 42
Amount of pens sold = p
Amount of pencils sold = p + 8
0.05(p + 8) + 0.20(p) = 8.90 each pen is $$ 0.20$ while each pencil is $$ 0.05$
0.05p + 0.4 + 0.20p = 8.90
0.25p = 8.50
Number of pens: 34
Number of pencils sold: 34 + 8 = 42
The correct option is C