Question

The self inductance of a coil is 5 m H. If a current of 2 A is flowing in it then the magnetic flux produced in the coil will be

• A. 0.01 Weber
• B. 10 Weber
• C. zero
• D. 1 Weber

Answer 1

The correct option is A 0.01 Weber

$emf=L\frac{dI}{dt}=\frac{d\varphi }{dt}$

$\Rightarrow LdI=d\varphi$

Integrating both side we will get,

$L\int dI=\int d\varphi$

$\Rightarrow 5\times {10}^{-3}\times 2=\varphi$

$\Rightarrow \varphi =0.01$ Weber