The separation between a node and the next antinode in a vibrating air column is 25 cm. If the speed of sound 1 in air is $340 m s^{- 1}$ , find the frequency of vibration of the air column.

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Solution

Distance between two nodes or antinodes

$\Rightarrow \frac{λ}{4} = 25 c m$

$\Rightarrow λ = 10 c m = 1 m$

$\Rightarrow n = \frac{v}{λ} = 340 H z$

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The separation between a node and the next antinode in a vibrating air column is 25 cm. If the speed of sound 1 in air is 340ms−1, find the frequency of vibration of the air column.

Distance between two nodes or antinodes ⇒λ4=25cm ⇒λ=10cm=1m ⇒n=vλ=340Hz

The separation between a node and the next antinode in a vibrating air column is 25 cm. If the speed of sound 1 in air is $340 m s^{- 1}$ , find the frequency of vibration of the air column.

Distance between two nodes or antinodes

$\Rightarrow \frac{λ}{4} = 25 c m$

$\Rightarrow λ = 10 c m = 1 m$

$\Rightarrow n = \frac{v}{λ} = 340 H z$