Question

The sequence $3,6,12,\mathrm{24....}$ function is

• A. $3.(2{)}^{n+1}$
• B. $3.(3{)}^{n-1}$
• C. $3.(2{)}^n$
• D. $3.(2{)}^{n-1}$

Answer 1

The correct option is D $3.(2{)}^{n-1}$

Given sequence is $3,6,12,\mathrm{24....}$.
When $n=1$, $3.(2{)}^{1-1}=3$ i.e. $3.(2{)}^{1-1}$
When $n=2$, $3.(2{)}^{2-1}=6$ i.e. $3.(2{)}^{2-1}$
When $n=3$, $3.(2{)}^{3-1}=12$ i.e. $3.(2{)}^{3-1}$
When $n=4$, $3.(2{)}^{4-1}=24$ i.i. $3.(2{)}^{4-1}$
So, $3,6,12,\mathrm{24..}$ is the function for the sequence is $3.(2{)}^{n-1}$.