The set of values of a for which the equation sinx(sinx+cosx)=a has real solutions is
A
[1−√2,1+√2]
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
[2−√3,2+√3]
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
[0,2+√3]
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
[1−√22,1+√22]
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D[1−√22,1+√22] We have, sinx(sinx+cosx)=a ⇒2sin2x+2sinxcosx=2a ⇒1−cos2x+sin2x=2a ⇒sin2x−cos2x=2a−1 This equation will have real solutions, if |2a−1|≤√1+1 ⇒1−√2≤2a≤1+√2 ⇒aϵ[1−√22,1+√22]