The shape of ${I F}_{4}$ will be:-

square planer

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tetrahedral

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pentagonal bipyramidal

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distorted tetrahedral

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Solution

The correct option is A square planer
$I F_{4}$ ( iodine tetrafluoride ) has an octahedral electron geometry, but the molecular geometry states that the atoms take a square planar shape. This is because iodine carries two lone pairs, one above and below the plane on the x-axis.
Hence, option A is correct.

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