The shape of the cross section of a canal is a trapezium. If the canal is 10 m wide at the top, 6 m wide at the bottom and the area of its cross section is 640 $m^{2}$ , find the depth of the canal.

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Solution

Area of trapezium = $\frac{1}{2} (a + b) d$

$\frac{1}{2} (10 + 6) \times d = 640$

$d = \frac{640 \times 2}{16} = 80 m$

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The shape of the cross section of a canal is a trapezium. If the canal is 10 m wide at the top, 6 m wide at the bottom and the area of its cross section is 640 m2, find the depth of the canal.

Area of trapezium = 12(a+b)d 12(10+6)×d=640 d=640×216=80 m

The shape of the cross section of a canal is a trapezium. If the canal is 10 m wide at the top, 6 m wide at the bottom and the area of its cross section is 640 $m^{2}$ , find the depth of the canal.

Area of trapezium = $\frac{1}{2} (a + b) d$

$\frac{1}{2} (10 + 6) \times d = 640$

$d = \frac{640 \times 2}{16} = 80 m$