Question

The shape of the top surface of a table is trapezium. Its parallel sides are 1 m and 1.4 m and the perpendicular distance between them is 0.9 m. Find its area.

Answer 1

$\mathrm{Area}\mathrm{of}\mathrm{a}\mathrm{trapezium}=\frac{1}{2}\times \left(\mathrm{Sum}\mathrm{of}\mathrm{parallel}\mathrm{sides}\right)\times \left(\mathrm{Distance}\mathrm{between}\mathrm{them}\right)$
$$\begin{gathered} =\left\{\frac{1}{2}\times \left(1+1.4\right)\times 0.9\right\}{\mathrm{m}}^2 \\ =\left(\frac{1}{2}\times 2.4\times 0.9\right){\mathrm{m}}^2 \\ =\left(1.2\times 0.9\right){\mathrm{m}}^2 \\ =1.08{\mathrm{m}}^2 \end{gathered}$$
$\mathrm{Hence},\mathrm{the}\mathrm{area}\mathrm{of}\mathrm{the}\mathrm{top}\mathrm{surface}\mathrm{of}\mathrm{the}\mathrm{table}\mathrm{is}1.08{\mathrm{m}}^2.$