The sharpness of resonance in a series L−C−R resonant circuit, as the resistance of the circuit is increased, goes on
A
increasing
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B
decreasing
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C
tends from zero to infinity
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D
tends from infinity to zero
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Solution
The correct option is D decreasing At resonance impedance becomes equal to R, therefore when we increase R the current flowing at the time of resonance decreases and therefore the sharpness of curve too decreases