The shortest distance between an octahedral and a tetrahedral void in FCC lattice would be

FCC जालक में अष्टफलकीय तथा चतुष्फलकीय रिक्ति के मध्य न्यूनतम दूरी होगी

\sqrt{3} a

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\frac{\sqrt{3} a}{2}

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\frac{\sqrt{3} a}{3}

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\frac{\sqrt{3} a}{4}

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Solution

The correct option is D $\frac{\sqrt{3} a}{4}$
Solution

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Similar questions

\sqrt{6}

In which of the following structures coordination number for cations and anions in the packed structure will be same ?

(a) $C l^{-}$ ions form fcc lattice and $N a^{+}$ ions occupy all octahedral voids of the unit cell

(b) $C a^{2 +}$ ions form fcc lattice and $F^{-}$ ions occupy all the eight tetrahedral voids of the unit cell

(d) $S^{2 -}$ ions form fcc lattice and $Z n^{2 +}$ ions go into alternate tetrahedral voids of the unit cell

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