The shortest distance between the lines →r=3→i+5→j+7→k+λ(→i+2→j+→k) and →r=−→i−→j−→k+μ(7→i−6→j+→k) is
165√5
265√5
365√5
465√5
d=|(→a2−→a1).(→b1×→b2)||→b1×→b2| d=465√5