The shortest distance between the skew lines r-r1-ta1 and r-r2-n a2- where r1-9j-2k- a1-3i-j-k- r2-6i-5j-10k- a2-3i-2j-4k is 3-a- Then the value of a is-

Given r_1=9j+2k, a_1=3i j+k, r_2= 6i 5j+10k, a_2= 3i+2j+4k, we have: r_2 r_1= 6i 14j+8k and a_1×a_2=i amp;j nbsp; amp;k nbsp; nbsp;3 amp; 1 nbs ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Condition for a Conic to Be a Pair of Straight Lines

The shortest ...

Question

The shortest distance between the skew lines $\to r =_{1} + t_{1} and \to r =_{2} + n - \to a_{2}, where_{1} = 9 j + 2 k,_{1} = 3 i - j + k,_{2} = - 6 i - 5 j + 10 k,_{2} = - 3 i + 2 j + 4 k$ is $3 \sqrt{a}$ . Then the value of $a$ is:

Open in App

Solution

Suggest Corrections

Similar questions

r = (6 i + 2 j + 2 k) + t (i - 2 j + 2 k)

F = (- 4 i - k) + s (3 i - 2 j - 2 k)

r = (6 i + 2 j + 2 k) + t (i - 2 j + 2 k)

r = (- 4 i - k) + s (3 i - 2 j - 2 k)

\vec{r} = 3 \hat{i} + 8 \hat{j} + 3 \hat{k} + λ (3 \hat{i} - \hat{j} + \hat{k}) and \vec{r} = - 3 \hat{i} - 7 \hat{j} + 6 \hat{k} + μ (- 3 \hat{i} + 2 \hat{j} + 4 \hat{k})

\vec{r} = (3 \hat{i} + 5 \hat{j} + 7 \hat{k}) + λ (\hat{i} - 2 \hat{j} + 7 \hat{k}) and \vec{r} = - \hat{i} - \hat{j} - \hat{k} + μ (7 \hat{i} - 6 \hat{j} + \hat{k})

\vec{r} = (\hat{i} + 2 \hat{j} + 3 \hat{k}) + λ (2 \hat{i} + 3 \hat{j} + 4 \hat{k}) and \vec{r} = (2 \hat{i} + 4 \hat{j} + 5 \hat{k}) + μ (3 \hat{i} + 4 \hat{j} + 5 \hat{k})

\vec{r} = (1 - t) \hat{i} + (t - 2) \hat{j} + (3 - t) \hat{k} and \vec{r} = (s + 1) \hat{i} + (2 s - 1) \hat{j} - (2 s + 1) \hat{k}

\vec{r} = (λ - 1) \hat{i} + (λ + 1) \hat{j} - (1 + λ) \hat{k} and \vec{r} = (1 - μ) \hat{i} + (2 μ - 1) \hat{j} + (μ + 2) \hat{k}

\vec{r} = (2 \hat{i} - \hat{j} - \hat{k}) + λ (2 \hat{i} - 5 \hat{j} + 2 \hat{k}) and, \vec{r} = (\hat{i} + 2 \hat{j} + \hat{k}) + μ (\hat{i} - \hat{j} + \hat{k})

\vec{r} = (\hat{i} + \hat{j}) + λ (2 \hat{i} - \hat{j} + \hat{k}) and, \vec{r} = 2 \hat{i} + \hat{j} - \hat{k} + μ (3 \hat{i} - 5 \hat{j} + 2 \hat{k})

\vec{r} = (8 + 3 λ) \hat{i} - (9 + 16 λ) \hat{j} + (10 + 7 λ) \hat{k}

\vec{r} = 15 \hat{i} + 29 \hat{j} + 5 \hat{k} + μ (3 \hat{i} + 8 \hat{j} - 5 \hat{k})

\to r = 3 i + 2 j - 4 k + λ (i + 2 j + 2 k)

\to r = (5 j - 2 k) + μ (3 i + 2 j + 6 k)

¯ r = (3^i + 5^j + 7^k) + λ (^i - 2^j +^k)

¯ r = (-^i -^j -^k) + μ (7^i - 6^j +^k)

Join BYJU'S Learning Program

Explore more

Join BYJU'S Learning Program