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B
√b2+c2
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C
√c2+a2
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D
√a2+b2+c2
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Solution
The correct option is B√b2+c2 The shortest distance of a point is always the perpendicular distance. The projection of the point (a,b,c) on the x-axis is (a,0,0). This distance is given by √b2+c2.