The SI unit of a physical quantity is pascal-second. The dimensional formula of this quantity will be:

$[M L^{- 1} T^{- 1}]$

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$[M^{- 1} L^{3} T^{0}]$

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$[M L^{2} T^{- 1}]$

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$[M L^{- 1} T^{- 2}]$

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Solution

The correct option is A
$[M L^{- 1} T^{- 1}]$

[pascal-second] $= \frac{M L T^{- 2}}{L^{2}} \times T$

$= M L^{- 1} T^{- 1}$

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