The SI unit of electric field intensity is

N C^{- 1}

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N C

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C N^{- 1}

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N C^{- 2}

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Solution

The correct option is A $N C^{- 1}$
$E = \frac{F}{q}$

Hence, SI unit of electric field intensity is $N / C = N C^{- 1}$

Answer-(A)

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Similar questions

Q. A uniform electric field

E = 2 \times 10^{3} N C^{- 1}

is acting along the positive x-axis. The flux of this field through a square of 10 cm on a side whose plane is parallel to the yz plane is:

Q. The electric field at

(30, 30) c m

due to a charge of

- 8 n C

at the origin in

N C^{- 1}

The electric field in a region is given by
$E = (2^i + 3^j) \times 10^{3} N C^{- 1}$
The electric flux through a rectangular surface $10 c m \times 20 c m$ held parallel to the y-z plance is

Q. The potential function of an electric field is given by

V = 2 x^{2} .

Determine strength of the electrostatic field at the point

(2 m, 0, 3 m) .

The electric flux for Gaussian surface A that enclose the charged particles in free space is

(g i v e n q_{1} = - 14 n C, q_{2} = 78.85 n C, q_{3} = - 56 n C)

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The SI unit of electric field intensity is

The correct option is A NC−1E=FqHence, SI unit of electric field intensity is N/C=NC−1Answer-(A)

The correct option is A $N C^{- 1}$
$E = \frac{F}{q}$

Hence, SI unit of electric field intensity is $N / C = N C^{- 1}$

Answer-(A)