Question

The side of an equilateral triangle of area $64\sqrt{3}c{m}^2$ is

• A. 12 cm
• B. 14 cm
• C. 16 cm
• D. 18 cm

Answer 1

The correct option is C 16 cm

Let the side of equilateral triangle is a cm

Then area of equilateral triangle=$\frac{\sqrt{3}}{4}{a}^2$ sq cm

But area of equilateral triangle given=$64\sqrt{3}c{m}^2$

$\frac{\sqrt{3}}{4}{a}^2=64\sqrt{3}c{m}^2$

$\Rightarrow a^2=64\times 4$

$\Rightarrow a^2=256$

$\Rightarrow a=16$cm