Given, I1−I2 = ₹3,120
T1 = 8 yrs, R1 = 12 %
T2 = 5 yrs, R2 = 14 %
and P1=P2=P
According to the question,
I1−I2 = ₹3,120
⇒P1×R1×T1100−P2×R2×T2100=3,120⇒P×12×8100−P×14×5100=3,120⇒P100[12×8−14×5]=3,120⇒P[96−70]=3,120×100⇒26P=3,12,000⇒P=3,12,00026
P = ₹12,000
Hence, the sum is ₹12,000.