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Question

The simplest form of the expression 1012127 is

A
27
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B
283
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C
27+i3
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D
1+i3
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Solution

The correct option is D 1+i3

We need to find simplest form of 1012127

=102i313i3

Taking conjugate, we get

= 1023133×1+3i31+3i3

= 102313312(3i3)2

= 10+30i32i318i228

= 10+28i3+1828

= 28(1+i3)28

= 1+i3


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