Question

The single-bonded metallic radius of sodium is $157$ pm. Assume that the increment between radii of different magnitudes is $60$ pm. The ionic radius $N{a}^{+}$ in pm is $(90+x)$. Find $x$.

Answer 1

Metallic radius is larger than ionic radius. The single-bonded metallic radius of sodium is 157 pm. The increment between radii of different magnitudes is 60 pm.Hence, the ionic radius of $Na$ in pm is $157ppm-60ppm=97ppm$.

$\therefore 90+x=97pm\Rightarrow x=7pm$