The singly-bonded metallic radius of Na is 154 pm. Assume that the increment between radii of different magnitudes is 60 pm. Ionic radius of Na+ is__________.
The correct option is C 94 pm
Covalent radius:One half of the distance between the nuclei (internuclear distance) of two covalently bonded atoms in homodiatomicmolecule is called the covalent radius of that atom.
Metallic Radius:Metal atoms are assumed to be closely packed spheres in the metallic crystal. These metal atom spheres areconsidered to touch one another in the crystal. One half of the internuclear distance between the two closestmetal atoms in the metallic crystal is called metallic radius.
Ionic radius:A neutral atom changes to a cation by the loss of one or more electrons and to an anion by the gain of one or more electrons. The magnitude of charge on cation and anion is equal to the number of electrons lost or gained respectively. The ionic radii of the ions present in an ionic crystal may be calculated from the inter molecular distance between the two ions.Here, ionic radius of Na+=154−60=94pm
Covalent radius:One half of the distance between the nuclei (internuclear distance) of two covalently bonded atoms in homodiatomicmolecule is called the covalent radius of that atom.
Metallic Radius:Metal atoms are assumed to be closely packed spheres in the metallic crystal. These metal atom spheres areconsidered to touch one another in the crystal. One half of the internuclear distance between the two closestmetal atoms in the metallic crystal is called metallic radius.
Ionic radius:A neutral atom changes to a cation by the loss of one or more electrons and to an anion by the gain of one or more electrons. The magnitude of charge on cation and anion is equal to the number of electrons lost or gained respectively. The ionic radii of the ions present in an ionic crystal may be calculated from the inter molecular distance between the two ions.Here, ionic radius of Na+=154−60=94pm
